Multiple Regression Analysis Model Formation: Checking Significance of Independent Variables
Use the following results:
Variable | Coefficient | Standard Error | t Statistic | p Value |
INTERCEPT | -0.02686 | 0.06905 | -0.39 | 0.7034 |
FOREIMP | 0.79116 | 0.06295 | 12.57 | 0.0000 |
MIDSOLE | 0.60484 | 0.07174 | 8.43 | 0.0000 |
A. Construct a 95% confidence interval estimate of the population slope between durability and forefoot shock-absorbing capability
Step 1: The formula for creating the confidence interval for the population parameter is given as follows:
{` Sample estimate ± tα/2 *standard error Step 2: To calculatetα/2, use the Excel function TINV. Go to Formulas -> More Functions -> Statistical -> TINV `}
In the TINV dialog box, enter the probability as 0.05 and degrees of freedom as 12 (=n – 2-1)
This gives the value of t12,0.05 as 2.17
Step 3: Use the formula described in Step 1 to get the confidence interval for the population slope.
{` Confidence interval= 0.79116 ± (2.17*0.06295) = 0.79116 ± (0.136) = (0.655, 0.927) `}
B. At the 0.05 level of significance, determine whether each independent variable make a significant contribution to the regression model. On the basis of these results, indicate the independent variables to include in this model.
{` Testing significance of the variable FOREIMP (b) Step 1: establish the null and alternate hypothesis: Null hypothesis: H0: b=0 Alternate hypothesis: H1:b ≠ 0 Step 2: t test will be used. α= 0.05 Step 3: Establish the decision criteria: Reject H0 when tcal > critical value Step 4: Critical value = 2.17 (from part A above) tcal = 12.57 (from the regression results given) Step 5: Since tcal > critical value, we reject the null hypothesisH0. Thus, the variable FOREIMP makes a significant contribution to the model Testing significance of the variable MIDSOLE (c) Step 1: Establish the null and alternate hypothesis: Null hypothesis: H0: c = 0 Alternate hypothesis: H1: c ≠ 0 Step 2: t test will be used. α= 0.05 Step 3: Establish the decision criteria: Reject H0 when tcal > critical value Step 4: Critical value = 2.167 (from part A above) tcal = 8.43 (from the regression results given) Step 5: Since tcal > critical value, we reject the null hypothesisH0. Thus, the variable MIDSOLE makes a significant contribution to the model `}
Therefore, we can conclude that both the given variable have a significant contribution to the explanatory power of the regression model. Therefore, both these variables should be included.
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