Chemistry Assignment Help with Degree of Dissociation
5.8 Degree of Dissociation
Degree of dissociation is the fraction of a mole of the reactant that underwent dissociation. It is represented by 'a'.
5.9 Relation between Vapour Density and Degree of Dissociation
The relation between vapour density and the degree of dissociation can be established only for a gaseous equilibrium who’s KP exists. For example,
Total concentration at equilibrium = c – ca + nca = c [1 – a + na] = c [1 + a (n – 1)]
Assuming that all the gaseous components at equilibrium behave ideally, we can apply ideal gas equation.
PV = nR =
\ V.D =
…(i) [since molar mass = 2 ´ V.D]As pressure of the system is given by,
, so putting the value of P in equation (i) givesV.D =
where r is the density of the gas or gaseous mixture expressed in g/litre.
If the equilibrium reaction is established in a closed vessel, then vapor density will be inversely proportional to the number of moles of the gaseous species as the density of the gaseous mixture (r) is a constant.
\
Let the initial vapour density and vapour density at equilibrium be ‘D’ and ‘d’ respectively, then for the given equilibrium
or
or
\
where ‘n’ represents the number of moles of gaseous product given by 1 mole of the gaseous reactant.
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