SUR 222 Plane Surveying
HOMEWORK #5 (20 pts)
Use engineering computation paper, Excel or a word processed document
- Compute the corrected (reduced) value of each of the following zenith angles:
Direct |
Reverse |
a. 880 51” 10” |
2710 09’ 10” |
b. 890 44’ 14” |
2700 15’ 24” |
c. 830 06’ 12” |
2760 52’ 28” |
- Given the following reduced zenith angles and slope distances, compute the horizontal and vertical distances.
Zenith angle |
Slope distance | |
a. |
890 03’ 10” |
234.76’ |
b. |
880 59’ 23” |
250.03’ |
c. |
890 51’ 14” |
1,322.70’ |
- A total station is set at a height of 4.37 feet above a control point which has an elevation of 3910.71 feet. A direct zenith angle reading of 880 49’ 27” and a reverse zenith angle of 2710 10’ 49” and a slope distance of 821.45 feet are observed to point K. The target height at point K is 6.00 feet. What is the elevation at point K? Be sure to correct the zenith angle to correctly do the computations.
- A total station is set up on point A. A backsight is observed at point B which has an elevation of 3902.44 feet. The height of the instrument is 4.89 feet and the height of the target is 5.73 feet. A direct zenith angle reading of 900 02’ 13” and reverse zenith angle reading of 2690 58’ 22” and a slope distance of 187.56 feet are observed. What is the elevation at point A? Be sure to correct the zenith angle to correctly do the computations.
- A total station is set over a control point at a height of 5.17 feet. The elevation at the control point is 3988.38 feet. The prism is set at a height of 6.00 feet. The following zenith angles and slope distances are measured to the prism pole as it is moved from one point to the next:
Point |
Zenith |
SD |
J |
890 29’ 14” |
287.43’ |
K |
860 14’ 58” |
254.39’ |
L |
920 48’ 22” |
214.87’ |
What are the elevations of points J, K and L?